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<p><span class="process-math">\(\left(\frac{2}{\pi} \right)^{1/2} y_1=\left(\frac{2}{\pi x}\right)^{1/2} \cos x \xlongequal[ ]{\textrm{denoted as}} J_{-1/2}(x)\)</span> is also a solution, which is called the Bessel function of order <span class="process-math">\(-1/2\text{.}\)</span> Thus, the general solution is</p>
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\begin{equation*}
y=C_1 J_{1/2}(x)+C_2 J_{-1/2}(x).
\end{equation*}
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